pyspark.pandas.Index.symmetric_difference#

Index.symmetric_difference(other, result_name=None, sort=None)[source]#

Compute the symmetric difference of two Index objects.

Parameters
otherIndex or array-like
result_namestr
sortTrue or None, default None

Whether to sort the resulting index. * True : Attempt to sort the result. * None : Do not sort the result.

Returns
symmetric_differenceIndex

Notes

symmetric_difference contains elements that appear in either idx1 or idx2 but not both. Equivalent to the Index created by idx1.difference(idx2) | idx2.difference(idx1) with duplicates dropped.

Examples

>>> s1 = ps.Series([1, 2, 3, 4], index=[1, 2, 3, 4])
>>> s2 = ps.Series([1, 2, 3, 4], index=[2, 3, 4, 5])
>>> s1.index.symmetric_difference(s2.index)
Index([1, 5], dtype='int64')

You can set name of result Index.

>>> s1.index.symmetric_difference(s2.index, result_name='pandas-on-Spark')
Index([1, 5], dtype='int64', name='pandas-on-Spark')

You can set sort to True, if you want to sort the resulting index.

>>> s1.index.symmetric_difference(s2.index, sort=True)
Index([1, 5], dtype='int64')

You can also use the ^ operator:

>>> (s1.index ^ s2.index)
Index([1, 5], dtype='int64')